According to the 7period for n^2 and n^31 (mod 7) LHS=RHS requires both to be 0 mod(7), so that for some n and k y^2=n*7^2 must equal k* 7^3 1 and therefore 7^2(n7k)=1 , impossible, since 7^2>1 I note the table format doesn't come out right you have to do it yourselves
X 1/2 y-1/3=8 x-1/3 y 1/2=9 by elimination method-Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreWeekly Subscription $249 USD per week until cancelled Monthly Subscription $799 USD per month until cancelled Holidays Promotion Annual Subscription $1999 USD for 12 months (40% off)
X 1/2 y-1/3=8 x-1/3 y 1/2=9 by elimination methodのギャラリー
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